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MySQL 分組查詢和聚合函數(shù)

瀏覽:5日期:2023-10-09 10:09:54

概述

相信我們經(jīng)常會(huì)遇到這樣的場(chǎng)景:想要了解雙十一天貓購(gòu)買化妝品的人員中平均消費(fèi)額度是多少(這可能有利于對(duì)商品價(jià)格區(qū)間的定位);或者不同年齡段的化妝品消費(fèi)占比是多少(這可能有助于對(duì)商品備貨量的預(yù)估)。

這個(gè)時(shí)候就要用到分組查詢,分組查詢的目的是為了把數(shù)據(jù)分成多個(gè)邏輯組(購(gòu)買化妝品的人員是一個(gè)組,不同年齡段購(gòu)買化妝品的人員也是組),并對(duì)每個(gè)組進(jìn)行聚合計(jì)算的過程:。

分組查詢的語(yǔ)法格式如下:

select cname, group_fun,... from tname [where condition] group by group_expression [having group_condition];

說明一下:

1、group_fun 代表聚合函數(shù),是指對(duì)分組的數(shù)據(jù)進(jìn)行聚合計(jì)算的函數(shù)。

2、group_expression 代表分組表達(dá)式,允許多個(gè),多個(gè)之間使用逗號(hào)隔開。

3、group_condition 分組之后,再對(duì)分組后的數(shù)據(jù)進(jìn)行條件過濾的過程。

4、分組語(yǔ)法中,select后面出現(xiàn)的字段 要么是group by后面的字段,要么是聚合函數(shù)的列,其他類型會(huì)報(bào)異常,我們下面的內(nèi)容中會(huì)詳細(xì)說明。

說分組之前,先來看看聚合函數(shù),聚合函數(shù)是分組查詢語(yǔ)法格式中重要的一部分。我們經(jīng)常需要匯總數(shù)據(jù)而不用把它們實(shí)際檢索出來,所以MySQL提供了專門的函數(shù)。使用這些函數(shù),可用于計(jì)算我們需要的數(shù)據(jù),以便分析和生成報(bào)表。

聚合函數(shù)

聚合函數(shù)有以下幾種。

函數(shù) 說明 AVG() 返回指定字段的平均值 COUNT() 返回查詢結(jié)果行數(shù) MAX() 返回指定字段的最大值  MIN() 返回指定字段的最小值 SUM() 返回指定字段的求和值

AVG()函數(shù)

AVG()通過對(duì)表中行數(shù)計(jì)數(shù)并計(jì)算特定列值之和,求得該列的平均值。 AVG()可用來返回所有列的平均值,也可以用來返回特定列或行的平均值。

下面示例返回用戶表中用戶的平均年齡:

mysql> select * from user2;+----+--------+------+----------+-----+| id | name | age | address | sex |+----+--------+------+----------+-----+| 1 | brand | 21 | fuzhou | 1 || 2 | helen | 20 | quanzhou | 0 || 3 | sol | 21 | xiamen | 0 || 4 | weng | 33 | guizhou | 1 || 5 | selina | 25 | NULL | 0 || 6 | anny | 23 | shanghai | 0 || 7 | annd | 24 | shanghai | 1 || 8 | sunny | NULL | guizhou | 0 |+----+--------+------+----------+-----+8 rows in setmysql> select avg(age) from user2;+----------+| avg(age) |+----------+| 23.8571 |+----------+1 row in set

注意點(diǎn):

1、AVG()只能用來確定特定數(shù)值列的平均值 。2、AVG()函數(shù)忽略列值為NULL的行,所以上圖中age值累加之后是除以7,而不是除以8。

COUNT()函數(shù)

COUNT()函數(shù)進(jìn)行計(jì)數(shù)。 可以用COUNT()確定表中符合條件的行的數(shù)目。

count 有 count(*)、count(具體字段)、count(常量) 三種方式來體現(xiàn) 下面 演示了count(*) 和 count(cname)的用法。

mysql> select * from user2;+----+--------+------+----------+-----+| id | name | age | address | sex |+----+--------+------+----------+-----+| 1 | brand | 21 | fuzhou | 1 || 2 | helen | 20 | quanzhou | 0 || 3 | sol | 21 | xiamen | 0 || 4 | weng | 33 | guizhou | 1 || 5 | selina | 25 | NULL | 0 || 6 | anny | 23 | shanghai | 0 || 7 | annd | 24 | shanghai | 1 || 8 | sunny | NULL | guizhou | 0 |+----+--------+------+----------+-----+8 rows in setmysql> select count(*) from user2 where sex=0;+----------+| count(*) |+----------+| 5 |+----------+1 row in setmysql> select count(age) from user2 where sex=0;+------------+| count(age) |+------------+| 4 |+------------+1 row in set

可以看到,都是取出女生的用戶數(shù)量,count(*) 比 count(age) 多一個(gè),那是因?yàn)閍ge中包含null值。

所以:如果指定列名,則指定列的值為空的行被COUNT()函數(shù)忽略,但如果COUNT()函數(shù)中用的是星號(hào)( *),則不忽略。

MAX()和MIN()函數(shù)

MAX()返回指定列中的最大值,MIN()返回指定列中的最小值。

mysql> select * from user2;+----+--------+------+----------+-----+| id | name | age | address | sex |+----+--------+------+----------+-----+| 1 | brand | 21 | fuzhou | 1 || 2 | helen | 20 | quanzhou | 0 || 3 | sol | 21 | xiamen | 0 || 4 | weng | 33 | guizhou | 1 || 5 | selina | 25 | NULL | 0 || 6 | anny | 23 | shanghai | 0 || 7 | annd | 24 | shanghai | 1 || 8 | sunny | NULL | guizhou | 0 |+----+--------+------+----------+-----+8 rows in setmysql> select max(age),min(age) from user2;+----------+----------+| max(age) | min(age) |+----------+----------+| 33 | 20 |+----------+----------+1 row in set

注意:同樣的,MAX()、MIN()函數(shù)忽略列值為NULL的行。

SUM函數(shù)

SUM()用來返回指定列值的和(總計(jì)) ,下面返回了所有年齡的總和,同樣的,忽略了null的值

mysql> select * from user2;+----+--------+------+----------+-----+| id | name | age | address | sex |+----+--------+------+----------+-----+| 1 | brand | 21 | fuzhou | 1 || 2 | helen | 20 | quanzhou | 0 || 3 | sol | 21 | xiamen | 0 || 4 | weng | 33 | guizhou | 1 || 5 | selina | 25 | NULL | 0 || 6 | anny | 23 | shanghai | 0 || 7 | annd | 24 | shanghai | 1 || 8 | sunny | NULL | guizhou | 0 |+----+--------+------+----------+-----+8 rows in setmysql> select sum(age) from user2;+----------+| sum(age) |+----------+| 167 |+----------+1 row in set

分組查詢

數(shù)據(jù)準(zhǔn)備,假設(shè)我們有一個(gè)訂貨單表如下(記載用戶的訂單金額和下單時(shí)間):

mysql> select * from t_order;+---------+-----+-------+--------+---------------------+------+| orderid | uid | uname | amount | time| year |+---------+-----+-------+--------+---------------------+------+| 20 | 1 | brand | 91.23 | 2018-08-20 17:22:21 | 2018 || 21 | 1 | brand | 87.54 | 2019-07-16 09:21:30 | 2019 || 22 | 1 | brand | 166.88 | 2019-04-04 12:23:55 | 2019 || 23 | 2 | helyn | 93.73 | 2019-09-15 10:11:11 | 2019 || 24 | 2 | helyn | 102.32 | 2019-01-08 17:33:25 | 2019 || 25 | 2 | helyn | 106.06 | 2019-12-24 12:25:25 | 2019 || 26 | 2 | helyn | 73.42 | 2020-04-03 17:16:23 | 2020 || 27 | 3 | sol | 55.55 | 2019-08-05 19:16:23 | 2019 || 28 | 3 | sol | 69.96 | 2020-09-16 19:23:16 | 2020 || 29 | 4 | weng | 199.99 | 2020-06-08 19:55:06 | 2020 |+---------+-----+-------+--------+---------------------+------+10 rows in set

單字段分組

即對(duì)于某個(gè)字段進(jìn)行分組,比如針對(duì)用戶進(jìn)行分組,輸出他們的用戶Id,訂單數(shù)量和總額:

mysql> select uid,count(uid),sum(amount) from t_order group by uid;+-----+------------+-------------+| uid | count(uid) | sum(amount) |+-----+------------+-------------+| 1 | 3 | 345.65 || 2 | 4 | 375.53 || 3 | 2 | 125.51 || 4 | 1 | 199.99 |+-----+------------+-------------+4 rows in set

多字段分組

即對(duì)于多個(gè)字段進(jìn)行分組,比如針對(duì)用戶進(jìn)行分組,再對(duì)他們不同年份的訂單數(shù)據(jù)進(jìn)行分組,輸出訂單數(shù)量和消費(fèi)總額:

mysql> select uid,count(uid) as nums,sum(amount) as totalamount,year from t_order group by uid,year;+-----+------+-------------+------+| uid | nums | totalamount | year |+-----+------+-------------+------+| 1 | 1 | 91.23 | 2018 || 1 | 2 | 254.42 | 2019 || 2 | 3 | 302.11 | 2019 || 2 | 1 | 73.42 | 2020 || 3 | 1 | 55.55 | 2019 || 3 | 1 | 69.96 | 2020 || 4 | 1 | 199.99 | 2020 |+-----+------+-------------+------+7 rows in set

分組前的條件過濾:where

這個(gè)很簡(jiǎn)單,就是再分組(group by)之前通過where關(guān)鍵字進(jìn)行條件過濾,取出我們需要的數(shù)據(jù),假設(shè)我們只要列出2019年8月之后的數(shù)據(jù),源數(shù)據(jù)只有6條合格的,有兩條年份一樣被分組的:

mysql> select uid,count(uid) as nums,sum(amount) as totalamount,year from t_order where time > ’2019-08-01’ group by uid,year;+-----+------+-------------+------+| uid | nums | totalamount | year |+-----+------+-------------+------+| 2 | 2 | 199.79 | 2019 || 2 | 1 | 73.42 | 2020 || 3 | 1 | 55.55 | 2019 || 3 | 1 | 69.96 | 2020 || 4 | 1 | 199.99 | 2020 |+-----+------+-------------+------+5 rows in set

分組后的條件過濾:having

有時(shí)候我們需要再分組之后再對(duì)數(shù)據(jù)進(jìn)行過濾,這時(shí)候就需要使用having關(guān)鍵字進(jìn)行數(shù)據(jù)過濾,再上述條件下,我們需要取出消費(fèi)次數(shù)超過一次的數(shù)據(jù):

mysql> select uid,count(uid) as nums,sum(amount) as totalamount,year from t_order where time > ’2019-08-01’ group by uid,year having nums>1;+-----+------+-------------+------+| uid | nums | totalamount | year |+-----+------+-------------+------+| 2 | 2 | 199.79 | 2019 |+-----+------+-------------+------+1 row in set

這邊需要注意區(qū)分where和having:

where是在分組(聚合)前對(duì)記錄進(jìn)行篩選,而having是在分組結(jié)束后的結(jié)果里篩選,最后返回過濾后的結(jié)果。

可以把having理解為兩級(jí)查詢,即含having的查詢操作先獲得不含having子句時(shí)的sql查詢結(jié)果表,然后在這個(gè)結(jié)果表上使用having條件篩選出符合的記錄,最后返回這些記錄,因此,having后是可以跟聚合函數(shù)的,并且這個(gè)聚集函數(shù)不必與select后面的聚集函數(shù)相同。

分組后的排序處理

order條件接在group by后面,也就是統(tǒng)計(jì)出每個(gè)用戶的消費(fèi)總額和消費(fèi)次數(shù)后,對(duì)用戶的消費(fèi)總額進(jìn)行降序排序的過程。

mysql> select uid,count(uid) as nums,sum(amount) as totalamount from t_order group by uid;+-----+------+-------------+| uid | nums | totalamount |+-----+------+-------------+| 1 | 3 | 345.65 || 2 | 4 | 375.53 || 3 | 2 | 125.51 || 4 | 1 | 199.99 |+-----+------+-------------+4 rows in setmysql> select uid,count(uid) as nums,sum(amount) as totalamount from t_order group by uid order by totalamount desc;+-----+------+-------------+| uid | nums | totalamount |+-----+------+-------------+| 2 | 4 | 375.53 || 1 | 3 | 345.65 || 4 | 1 | 199.99 || 3 | 2 | 125.51 |+-----+------+-------------+4 rows in set

分組后的limit 限制

limit限制關(guān)鍵字一般放在語(yǔ)句的最末尾,比如基于我們上面的搜索,我們?cè)賚imit 1,只取出消費(fèi)額最高的那條,其他跳過。

mysql> select uid,count(uid) as nums,sum(amount) as totalamount from t_order group by uid order by totalamount desc limit 1;+-----+------+-------------+| uid | nums | totalamount |+-----+------+-------------+| 2 | 4 | 375.53 |+-----+------+-------------+1 row in set

關(guān)鍵字的執(zhí)行順序

我們看到上面那我們用了 where、group by、having、order by、limit這些關(guān)鍵字,如果一起使用,他們是有先后順序,順序錯(cuò)了會(huì)導(dǎo)致異常,語(yǔ)法格式如下:

select cname from tname where [原表查詢條件] group by [分組表達(dá)式] having [分組過濾條件] order by [排序條件] limit [offset,] count;

mysql> select uid,count(uid) as nums,sum(amount) as totalamount from t_order where time > ’2019-08-01’ group by uid having totalamount>100 order by totalamount desc limit 1;+-----+------+-------------+| uid | nums | totalamount |+-----+------+-------------+| 2 | 3 | 273.21 |+-----+------+-------------+1 row in set

總結(jié)

1、分組語(yǔ)法中,select后面出現(xiàn)的字段 要么是group by后面的字段,要么是聚合函數(shù)的列,其他類型會(huì)報(bào)異常:可以自己試試。

2、分組關(guān)鍵字的執(zhí)行順序:where、group by、having、order by、limit,順序不能調(diào)換,否則會(huì)報(bào)異常:可以自己試試。

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標(biāo)簽: MySQL 數(shù)據(jù)庫(kù)
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