登錄頁面點擊登錄后查詢不出數據,無法成功登陸,但是在數據庫中進行查詢操作是可以成功的,是什么原因呢?
問題描述
<?php
session_start();
error_reporting(E_ERROR);
$zh=$_POST['zh'];
$password=$_POST['password'];
$user=$_POST['user'];
if(!isset($user)){
echo "<script> alert('請選擇用戶類型');</script>";
echo "<script> history.go(-1);</script>";
}
$conn=mysqli_connect("localhost","8admin","8admin")or die('連接數據庫失敗');
$db=mysqli_select_db($conn,"8_com");
$sql1="SELECT*FROM admin WHERE admin_id ='$zh' AND password='$password' ";
$sql2="select * from teacher where teach_id ='$zh' and password='$password' ";
$sql3="select * from student where stuno ='$zh' and password='$password' ";
mysqli_query($conn,"set names utf8");
switch($user){
case 1:$result=mysqli_query($conn,$sql)or die('查詢不到');
$row = mysqli_fetch_array($conn,$result);
$count=$row[0];
if($count!=""){
$url="index_admin.php";
$_SESSION['admin_name']=$row['name'];
$_SESSION['admin_id']=$row['admin_id'];
echo "<script type='text/javascript'>"."location.href='".$url."'"."</script>";
}
else {
echo "<script> alert('賬戶或密碼錯誤');</script>";
echo "<script> history.go(-1);</script>";
}
break;
case 2:$result=mysqli_query($sql2,$conn);
$result=mysqli_query($sql2,$conn)or die('查詢不到');
$row = mysqli_fetch_array($result);
$count=$row[0];
if($count!=""){
$url="index_teacher.php";
$_SESSION['teacher_name']=$row['name'];
$_SESSION['teacher_id']=$row['teach_id'];
echo "<script type='text/javascript'>"."location.href='".$url."'"."</script>";
}
else {
echo "<script> alert('賬戶或密碼錯誤');</script>";
echo "<script> history.go(-1);</script>";
}
break;
case 3:$result=mysqli_query($sql3,$conn);
$result=mysqli_query($sql3,$conn)or die('查詢不到');
$row = mysqli_fetch_array($result);
$count=$row[0];
if($count!=""){
$url="index_stu.php";
$_SESSION['stu_name']=$row['name'];
$_SESSION['stu_id']=$row['stuno'];
echo "<script type='text/javascript'>"."location.href='".$url."'"."</script>";
}
else {
echo "<script> alert('賬戶或密碼錯誤');</script>";
echo "<script> history.go(-1);</script>";
}
break;
default :break;
}
mysqli_close($conn);
?>
問題解答
回答1:后端斷點打印是否能夠拿到數據
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