問(wèn)題描述

現(xiàn)在在做一個(gè)項(xiàng)目，需要用到websocket，需要python去連接websocket，但是不知道怎么用python連接websocket，找了好久沒找到，求各位大佬幫忙~~

問(wèn)題解答

pip3 install gevent-websocketpip3 install gunicorn

app.py demo

from geventwebsocket.handler import WebSocketHandlerfrom gevent.pywsgi import WSGIServerapp = Flask(__name__)@app.route(’/echo/’)def echo(): if request.environ.get(’wsgi.websocket’):ws = request.environ[’wsgi.websocket’]while True: msg = ws.receive() ws.send(msg)if __name__ == ’__main__’: http_server = WSGIServer((’’, 5000), app, handler_class=WebSocketHandler) http_server.serve_forever()

使用 gunicorn 啟動(dòng) 指定用 gevent-websocket

gunicorn -k geventwebsocket.gunicorn.workers.GeventWebSocketWorker app:appdjango 使用 Django-websocket

https://github.com/archever/p...

感謝各位，百度了好久都找不到解決辦法，樓上這位大神的應(yīng)該可以用的，不過(guò)我看不太懂，感恩，上谷歌果然有收獲，果斷棄用百度

這是別人github上面的，可以用

# install ws4py# pip install ws4py# easy_install ws4pyfrom ws4py.client.threadedclient import WebSocketClientclass DummyClient(WebSocketClient): def opened(self):self.send('www.baidu.com') def closed(self, code, reason=None):print 'Closed down', code, reason def received_message(self, m):print mif __name__ == ’__main__’: try:ws = DummyClient(’ws://10.222.138.163:1889/websocket’, protocols=[’chat’])ws.connect()ws.run_forever() except KeyboardInterrupt:ws.close()回答3：

建議使用tornado，它支持websocket，知乎后端就是使用tornado構(gòu)建的